Chemical Reactions

A chemical reaction rearranges atoms from reactants into new products, breaking old bonds and forming new ones. Mass is conserved (atoms are neither created nor destroyed), so every equation must be balanced. The eight fundamental reaction types below cover the vast majority of chemistry encountered from high school through undergraduate courses.

#TypeGeneral FormKey Clue
1SynthesisA + B → ABTwo or more reactants → one product
2DecompositionAB → A + BOne reactant → two or more products
3Single DisplacementA + BC → AC + BFree element displaces one ion in compound
4Double DisplacementAB + CD → AD + CBIons swap partners; often precipitate or gas
5Combustionfuel + O₂ → CO₂ + H₂OFuel reacts with oxygen; releases heat & light
6Acid-Baseacid + base → salt + H₂OProton transfer (neutralisation)
7Redoxoxidiser + reducer → productsElectrons transferred between species
8Precipitationions(aq) → solid↓ + ions(aq)Insoluble solid forms from two solutions

Synthesis (Combination) A + B → AB

In a synthesis reaction two or more substances combine to form a single, more complex product. The reactants can be elements or compounds.

A + B AB
Balanced EquationNotes
2H₂ + O₂ → 2H₂OFormation of water; extremely exothermic
2Na + Cl₂ → 2NaClFormation of table salt; vigorous reaction
CaO + H₂O → Ca(OH)₂Slaked lime; used in construction
3H₂ + N₂ → 2NH₃Haber-Bosch process; industrial ammonia synthesis
SO₃ + H₂O → H₂SO₄Formation of sulfuric acid
Industrial/Natural uses: The Haber-Bosch process ($\text{N}_2 + 3\text{H}_2 \rightarrow 2\text{NH}_3$) produces ~170 million tonnes of ammonia per year for fertilisers. Volcanic eruptions form new minerals via synthesis. Photosynthesis combines CO₂ and H₂O into glucose.
Home experiment: Dry mix: combine 1 tsp citric acid powder and 1 tsp baking soda in a dry bowl — nothing happens (no water catalyst). Add a few drops of water and feel the temperature drop as they combine into sodium citrate + CO₂ + H₂O. Safe, edible.

Problem Set

Balance: H₂ + Cl₂ → HCl
Balance: Al + O₂ → Al₂O₃
Balance: Mg + N₂ → Mg₃N₂

Decomposition AB → A + B

A single compound breaks down into two or more simpler substances. Energy input (heat, light, or electricity) is usually required.

AB A + B
Balanced EquationNotes
2H₂O → 2H₂ + O₂Electrolysis of water
2HgO → 2Hg + O₂Heat mercury(II) oxide; historic experiment
CaCO₃ → CaO + CO₂Calcination of limestone at ~840 °C
2H₂O₂ → 2H₂O + O₂Catalytic decomposition of hydrogen peroxide
2KClO₃ → 2KCl + 3O₂Potassium chlorate heated; lab O₂ source
Industrial/Natural uses: Limestone calcination ($\text{CaCO}_3 \rightarrow \text{CaO} + \text{CO}_2$) produces quicklime for cement. Electrolysis of water generates hydrogen fuel. Body uses catalase enzyme to decompose H₂O₂ to water.
Home experiment (Elephant Toothpaste): Pour 3% H₂O₂ into a bottle with a squirt of dish soap and a spoonful of dry active yeast dissolved in warm water. The yeast catalyses rapid decomposition of H₂O₂, releasing O₂ that foams through the soap. Warm to touch — exothermic.

Problem Set

Balance: H₂O₂ → H₂O + O₂
Balance: Ag₂O → Ag + O₂
Balance: NaHCO₃ → Na₂CO₃ + H₂O + CO₂ (decomposition of baking soda on heating)

Single Displacement A + BC → AC + B

A more reactive free element displaces a less reactive element from a compound. Reactivity (activity) series governs whether the reaction occurs.

A + BC AC + B
Balanced EquationNotes
Zn + 2HCl → ZnCl₂ + H₂Zinc displaces hydrogen from hydrochloric acid
Fe + CuSO₄ → FeSO₄ + CuIron displaces copper; copper deposits on nail
2Al + 6HCl → 2AlCl₃ + 3H₂Aluminium dissolves in hydrochloric acid
Mg + 2HCl → MgCl₂ + H₂↑Vigorous; magnesium more reactive than zinc
Cl₂ + 2NaBr → 2NaCl + Br₂Halogen displacement; chlorine above bromine
Industrial/Natural uses: Thermite reaction (Al displacing Fe) welds railway tracks. Hydrometallurgy uses more reactive metals to extract copper from solutions. Galvanising (zinc coating steel) exploits the activity series to protect iron.
Home experiment: Place steel wool in a jar of white vinegar (dilute acetic acid). Hydrogen gas bubbles will form as iron reacts with the acid. After a few minutes the wool darkens and loses structural integrity. The solution turns pale yellow-green (Fe²⁺ ions).

Problem Set

Balance: Cu + AgNO₃ → Cu(NO₃)₂ + Ag
Balance: Na + H₂O → NaOH + H₂
Balance: Fe + H₂SO₄ → Fe₂(SO₄)₃ + H₂ (Fe³⁺ product)

Double Displacement (Metathesis) AB + CD → AD + CB

Ions from two compounds exchange partners. The reaction is driven by formation of a precipitate, a gas, or a weakly ionised compound (like water).

AB + CD AD + CB
Balanced EquationNotes
NaCl + AgNO₃ → AgCl↓ + NaNO₃Classic precipitation test for chloride ions
BaCl₂ + Na₂SO₄ → BaSO₄↓ + 2NaClBarium sulfate precipitate; qualitative test
HCl + NaOH → NaCl + H₂OStrong acid-base neutralisation
Pb(NO₃)₂ + 2KI → PbI₂↓ + 2KNO₃Vivid yellow lead(II) iodide precipitate
Na₂CO₃ + CaCl₂ → CaCO₃↓ + 2NaClWhite calcium carbonate precipitate
Industrial/Natural uses: Water softening removes Ca²⁺/Mg²⁺ ions via precipitation with Na₂CO₃. Gravimetric analysis in analytical chemistry uses metathesis to form known precipitates for quantification. Scale formation in pipes is metathesis between dissolved ions.
Home experiment: Mix a solution of Epsom salts (MgSO₄) with washing soda (Na₂CO₃) — white magnesium carbonate precipitate forms immediately. Alternatively: mix vinegar (CH₃COOH + H⁺) with baking soda (NaHCO₃) — double displacement produces CO₂ bubbles, water and sodium acetate.

Problem Set

Balance: K₂SO₄ + BaCl₂ → BaSO₄↓ + KCl
Balance: H₂SO₄ + NaOH → Na₂SO₄ + H₂O
Balance: FeCl₂ + Na₂S → FeS↓ + NaCl

Combustion fuel + O₂ → CO₂ + H₂O

Complete combustion occurs with excess oxygen producing CO₂ and H₂O. Incomplete combustion (limited O₂) yields toxic CO and particulate soot (C).

Fuel + O₂ CO₂ + H₂O
Balanced EquationNotes
CH₄ + 2O₂ → CO₂ + 2H₂OMethane (natural gas); complete combustion
C₃H₈ + 5O₂ → 3CO₂ + 4H₂OPropane; camping stove fuel
2C₂H₂ + 5O₂ → 4CO₂ + 2H₂OAcetylene; oxy-acetylene welding
C + O₂ → CO₂Complete combustion of carbon
2C₈H₁₈ + 25O₂ → 16CO₂ + 18H₂OOctane (petrol); complete combustion
Industrial/Natural uses: Fossil fuel power stations, internal combustion engines, gas turbines, and rocket propulsion all rely on combustion. Wildfires and metabolic oxidation of glucose in cells are biological combustion analogues.
Home experiment: Light a candle in still air (blue flame base = complete; yellow tip = incomplete). Hold a cold ceramic plate above the flame briefly — observe the black soot (carbon) deposited, evidence of incomplete combustion. Compare with a gas cooker flame (mostly blue = more complete).

Problem Set

Balance: C₂H₆ + O₂ → CO₂ + H₂O (complete combustion of ethane)
Balance: C₄H₁₀ + O₂ → CO₂ + H₂O (butane, complete)
Balance: C₆H₁₂O₆ + O₂ → CO₂ + H₂O (combustion of glucose)

Acid-Base (Neutralisation) acid + base → salt + H₂O

An acid donates H⁺ to a base (Brønsted-Lowry definition). The resulting ionic compound is a salt, and water is usually produced. Net ionic equation: $\text{H}^+ + \text{OH}^- \rightarrow \text{H}_2\text{O}$.

Acid + Base Salt + H₂O
Balanced EquationNotes
HCl + NaOH → NaCl + H₂OStrong acid + strong base; salt solution neutral
H₂SO₄ + 2KOH → K₂SO₄ + 2H₂ODiprotic acid requires 2 mol base
CH₃COOH + NaHCO₃ → CH₃COONa + H₂O + CO₂Acetic acid + baking soda; gas produced
H₃PO₄ + 3NaOH → Na₃PO₄ + 3H₂OTriprotic acid requires 3 mol base
2HNO₃ + Ca(OH)₂ → Ca(NO₃)₂ + 2H₂ONitric acid + calcium hydroxide
Industrial/Natural uses: Antacids neutralise excess stomach acid (HCl + Mg(OH)₂ → MgCl₂ + H₂O). Water treatment adjusts pH with lime. Fertiliser production combines acids and bases. Soaps are made by saponification (a base-driven reaction).
Home experiment: Red cabbage pH indicator: boil red cabbage leaves and strain the purple liquid. Add drops to vinegar (acid — turns pink), water (neutral — stays purple), and baking soda solution (base — turns green/yellow). Titrate vinegar with baking soda solution until neutral (purple).

Problem Set

Balance: HBr + Ca(OH)₂ → CaBr₂ + H₂O
Balance: H₃PO₄ + NaOH → NaH₂PO₄ + H₂O (partial neutralisation)
Balance: Al(OH)₃ + H₂SO₄ → Al₂(SO₄)₃ + H₂O

Redox (Oxidation-Reduction) electron transfer

Oxidation is loss of electrons (OIL); reduction is gain of electrons (RIG). The species that loses electrons is the reducing agent; the one that gains electrons is the oxidising agent. Oxidation numbers track electron bookkeeping.

Oxidiser + Reducer Products
Balanced EquationOxidation change
2Fe + 3Cl₂ → 2FeCl₃Fe: 0 → +3 (oxidised); Cl: 0 → −1 (reduced)
Cu + 2AgNO₃ → Cu(NO₃)₂ + 2AgCu: 0 → +2; Ag: +1 → 0
4Fe + 3O₂ → 2Fe₂O₃Rusting; Fe: 0 → +3; O: 0 → −2
2Mg + O₂ → 2MgOMg: 0 → +2; bright white flame
Zn + CuSO₄ → ZnSO₄ + CuZn: 0 → +2 (oxidised); Cu: +2 → 0 (reduced)
Industrial/Natural uses: Electroplating (Cr, Ni, Au coatings), smelting (reduction of ore: Fe₂O₃ + 3CO → 2Fe + 3CO₂), lithium-ion batteries, photosynthesis/respiration, bleaching, and corrosion protection all rely on redox chemistry.
Home experiment (Grow Silver Crystals): Dissolve a small amount of silver nitrate in water in a clear glass (handle with care — stains skin). Place a clean copper coin in the solution. Within minutes, silver crystals grow on the copper surface as Cu is oxidised to Cu²⁺ and Ag⁺ is reduced to Ag metal. Solution turns blue (Cu²⁺).

Problem Set

Balance: Al + Fe₂O₃ → Al₂O₃ + Fe (thermite)
Balance: MnO₂ + HCl → MnCl₂ + Cl₂ + H₂O
Balance: Fe₂O₃ + CO → Fe + CO₂ (blast furnace reduction)

Precipitation ions → solid↓

When two aqueous solutions are mixed, ions combine to form an insoluble ionic compound that separates from solution as a solid precipitate. Solubility rules determine which combinations precipitate.

AB(aq) + CD(aq) AD↓ + CB(aq)
Balanced EquationPrecipitate colour
Pb(NO₃)₂ + 2NaI → PbI₂↓ + 2NaNO₃Bright yellow
AgNO₃ + NaCl → AgCl↓ + NaNO₃White (turns grey in light)
BaCl₂ + K₂SO₄ → BaSO₄↓ + 2KClWhite; insoluble even in acid
FeCl₃ + 3NaOH → Fe(OH)₃↓ + 3NaClRust-brown
Cu(NO₃)₂ + 2NaOH → Cu(OH)₂↓ + 2NaNO₃Pale blue
Industrial/Natural uses: Qualitative analysis identifies unknown ions by their precipitate colours. Water treatment removes heavy metal ions as hydroxide precipitates. Formation of kidney stones (calcium oxalate) is an in-vivo precipitation reaction. Stalagmites form via CaCO₃ precipitation.
Home experiment: Dissolve 1 tbsp Epsom salts (MgSO₄) in 100 mL warm water. Dissolve 1 tbsp washing soda (Na₂CO₃) in another 100 mL. Mix them together — a white precipitate of MgCO₃ forms immediately. Filter through a coffee filter to collect the solid. Rinse with water.

Problem Set

Balance: CaCl₂ + Na₂CO₃ → CaCO₃↓ + NaCl
Balance: MgCl₂ + NaOH → Mg(OH)₂↓ + NaCl
Balance: AlCl₃ + NaOH → Al(OH)₃↓ + NaCl

Master Balancing Guide

A balanced equation has equal numbers of each atom on both sides and equal total charge. Use coefficients only — never change subscripts.

Step-by-Step Algorithm

  1. Write the unbalanced skeleton — correct formulae for all reactants and products with an arrow.
  2. Count atoms of each element on each side. List the imbalances.
  3. Balance metals first, then non-metals, then hydrogen, and save oxygen for last.
  4. Use the smallest integer coefficients that balance every element simultaneously. Start with the most complex formula and work outwards.
  5. Verify — recount all atoms and charge. Reduce coefficients by their GCF if needed.

Worked Examples

DifficultySkeletonBalanced
EasyH₂ + O₂ → H₂O2H₂ + O₂ → 2H₂O
EasyNa + H₂O → NaOH + H₂2Na + 2H₂O → 2NaOH + H₂
MediumFe + O₂ → Fe₂O₃4Fe + 3O₂ → 2Fe₂O₃
MediumAl + H₂SO₄ → Al₂(SO₄)₃ + H₂2Al + 3H₂SO₄ → Al₂(SO₄)₃ + 3H₂
HardC₆H₁₂O₆ + O₂ → CO₂ + H₂OC₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O

Oxidation Number Method (for Redox)

  1. Assign oxidation numbers to every atom using standard rules (pure element = 0; O usually −2; H usually +1; sum of compound = 0).
  2. Identify which atoms change oxidation number. Calculate the magnitude of change for each.
  3. Multiply coefficients so that the total electrons lost (oxidation) equals total electrons gained (reduction) — this is the electron balance.
  4. Balance the remaining atoms (not involved in electron transfer) by inspection. Check charge balance in ionic equations.
  5. Verify atom counts and charge on both sides.

Example: Balance $\text{KMnO}_4 + \text{HCl} \rightarrow \text{KCl} + \text{MnCl}_2 + \text{Cl}_2 + \text{H}_2\text{O}$

Mn goes +7 → +2 (gain 5e⁻, reduced). Cl goes −1 → 0 (loses 1e⁻ per Cl atom, oxidised). To equalise: 1 Mn × 5e⁻ = 5 Cl × 1e⁻. Coefficient 2 KMnO₄ and 10 HCl for the redox Cl; then balance remaining Cl and H by inspection:

2KMnO₄ + 16HCl → 2KCl + 2MnCl₂ + 5Cl₂ + 8H₂O

Reaction Energy

Every reaction involves breaking existing bonds (requires energy) and forming new bonds (releases energy). The net difference is the enthalpy change $\Delta H$.

  • Exothermic ($\Delta H < 0$): products have lower energy than reactants; heat is released to surroundings. Examples: combustion, neutralisation, rusting.
  • Endothermic ($\Delta H > 0$): products have higher energy than reactants; heat is absorbed from surroundings. Examples: photosynthesis, dissolving ammonium nitrate, cooking.
  • Activation energy ($E_a$): minimum energy needed to initiate the reaction — the "energy hill" that must be surmounted regardless of whether the reaction is exo- or endothermic.
  • Catalysts lower $E_a$ without changing $\Delta H$, speeding up reactions by providing an alternative pathway.
Exothermic (ΔH < 0) Energy Reaction coordinate → Ea ΔH R P Endothermic (ΔH > 0) Energy Reaction coordinate → Ea ΔH R P

The enthalpy change can be calculated from bond energies: $$\Delta H = \sum E_\text{bonds broken} - \sum E_\text{bonds formed}$$ or from Hess's Law by combining known reaction enthalpies. Standard enthalpy of formation values ($\Delta H_f^\circ$) allow calculation of any reaction enthalpy: $$\Delta H_\text{rxn}^\circ = \sum \Delta H_f^\circ(\text{products}) - \sum \Delta H_f^\circ(\text{reactants})$$